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Mathematics 16 Online
OpenStudy (anonymous):

find the value of X. pic shown

OpenStudy (anonymous):

|dw:1372975336857:dw|

OpenStudy (anonymous):

you need to work out the bottom length of the right side triangle, using pythagoras. Then you can use that to work out the bottom length of the left triangle. and pythagoras again to get x

OpenStudy (anonymous):

|dw:1372976693408:dw| what if the diagram was drawn like that?

OpenStudy (anonymous):

Yeah my fault, brain fart.

OpenStudy (anonymous):

no its fine. I was going to say x is 15 aswell

OpenStudy (anonymous):

\[x\text{ = }\sqrt{\left(25-\sqrt{15^2-9^2}\right)^2+9^2}=5 \sqrt{10}\]

OpenStudy (anonymous):

i'm still a little confused...

OpenStudy (mertsj):

|dw:1372986781002:dw|

OpenStudy (anonymous):

so i use a^2 + b^2 = c^2

OpenStudy (mertsj):

Find AB using the Pythagorean Theorem

OpenStudy (mertsj):

Then find AC by subtracting AB from 25

OpenStudy (mertsj):

Then find x using the Pythagorean Theorem.

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

oh okay! thanks a bunch. i just needed to know what i should've with the numbers.

OpenStudy (mertsj):

yw

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