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find the value of X. pic shown
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|dw:1372975336857:dw|
you need to work out the bottom length of the right side triangle, using pythagoras. Then you can use that to work out the bottom length of the left triangle. and pythagoras again to get x
|dw:1372976693408:dw| what if the diagram was drawn like that?
Yeah my fault, brain fart.
no its fine. I was going to say x is 15 aswell
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\[x\text{ = }\sqrt{\left(25-\sqrt{15^2-9^2}\right)^2+9^2}=5 \sqrt{10}\]
i'm still a little confused...
|dw:1372986781002:dw|
so i use a^2 + b^2 = c^2
Find AB using the Pythagorean Theorem
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Then find AC by subtracting AB from 25
Then find x using the Pythagorean Theorem.
yes
oh okay! thanks a bunch. i just needed to know what i should've with the numbers.
yw
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