Polynomial question HELPPP!!! tyvm guys :)
solve the equation \[2x ^{3}-7x ^{2}-52x-55=0\], given that \[3-2\sqrt{5}\] is one root.
are you certain this is the correct question?
\(3 + 2\sqrt{5}\) is an other root since roots of polynomials always exist in pairs. Now you just need to find the last one.
to me, let other roots are p, r. therefore, \[(3-2\sqrt 5) +p +r = -7\\(3-2\sqrt 5) *p*r =55\] 2 variables, 2 equations, solve for p and r
you mean 7/2 and 55/2 right?
I gave the way, not solution, I didn't calculate
no the sum of the roots and the product of the roots... you wrote it wrong
where did you get that from?
You were given a root. The other root would be the conjugate of the given root.
loser66's method seems to laborious cause there is teh 3-2root5 which is a pain to simplify and solve with
Actually, do it this way:
|dw:1372992860094:dw|
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