Question

What is the length of AD?
Please Help!!!!!!

Answer 1

BAM = x
so;BAC = 2x

since AMis amedian
BM =MC
and AC = 12 (guven)

for AMCtriangel
sin2x/MC = sinAMC/12
sinAMC = 12sin2x/MC--------1

for ABM trinagel
Sin(180-AMC)/AB = sinx/MB
sin(180-AMC) = sinAMC = ABsinx/MB--------2

1 = 2
ABsinx/MB = 12sin2x/MC

ABsinx= 12.2.sinx.cosx (b'coz MC=MB]
AB/24 = cosx-----3

to ABDtriangel
cosx = AB/AD------4

3=4
AD = 24

Answer 2

........24

Answer 3

Wrong

Answer 4

o

Answer 5

well i suck at math

Answer 6

first find ac .... then u will get ad

Answer 7

lol