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cos^[(pi/2)-x]/ cos x Match the trig expression with one of the following a) csc x b) tan x c) sin^2 x d) sin x tan x e) sec^2 x f)sec^2 x + tan^2 x
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cos^[(pi/2)-x]/ cos x = sin x/ cos x = tan x Hence option b is correct
cos^2[(pi/2)-x]/cos x there was a typo is the answer still the same?
well, the answer will still hold, with just an extra sine function so $$ \cfrac{cos^2\pmatrix{\frac{\pi}{2}-x}}{cos(x)}\\ \implies \cfrac{sin^2(x)}{cos(x)} \implies sin(x)\cfrac{sin(x)}{cos(x)} \implies sin(x)tan(x) $$
@jdoe0001 could you explain how you got the first part?
http://1.bp.blogspot.com/-57vrQkzCnVA/TxfkOuTBs6I/AAAAAAAABWU/R91jwBewUyE/s1600/cofunction+identities.png cofunction identities
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