Write an equation in standard form of the line that passes through the given point and has the given slope m (–4, 3); m = 1/2

Question

mathstudent55 · Answer

Since you have the slope, start with the slope-intercept form of a line:
y = mx + b,
where m = slope.
Plug in m = 1/2, x = -4, and y = 3.
Solve for b.
Then put it in the form ax + by + c = 0

anonymous · Answer

@mathstudent55  so b=1.5?

mathstudent55 · Answer

y = mx + b
3 = (1/2)(-4) + b
3 = -2 + b
5 = b
b = 5

anonymous · Answer

ohh ok i see now thanks so much

mathstudent55 · Answer

Now plug in b into y = (1/2)x + b
Then move all terms to the left equaling zero.
Write it in the form ax + by + c = 0

anonymous · Answer

@mathstudent55  so (1/2)x+y = 5?

mathstudent55 · Answer

y = (1/2)x + 5
Subtract both (1/2)x and 5 to the left side:
-(1/2)x + y - 5 = 0
Multiply both sides by -2:
x - 2y + 10 = 0

anonymous · Answer

ok thanks