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\[\sqrt{x+2}=10-x\]
Start by squaring both sides to remove the radical: \[x+2=100 -20x +x^2\] Subtract x and 2 from both sides: \[0=x^2 -21x +98\] From here, you could try to factor, but I would just plug into the quadratic formula. If you'd like more assistance with this let me know.
do you know if the answer would be 7 or 14 or both because im not really sure how to check for extraneous solutions
Plug it back in the original equation, if it gives an untrue statement=extraneous
For extraneous solutions just substitute back the values in the original equation. If you get any absurd thing, its a extr. solution
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