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sqrt!!!
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\[\sqrt{n+5}=n-1\]
Start by squaring both sides, this eliminates the radical: \[n+5 = n^2 -2n +1\] Subtract n and 5 from both sides: \[n^2 -3n -4 = 0\] Now, try solving this by factoring or plugging in to the quadratic equation. Be sure to check them in the original.
wait what?
Where did I lose you?
the first part. im sorry I really don't understand these
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Ok. We're going to square both sides. On the left side, we cancel out the square root. On the right side we have: \[(n-1)^2 = (n-1)(n-1)= n^2 -n -n +1 = n^2 -2n +1\] using the FOIL method.
okay
can I just have the answer? im sorry im really trying to get past this section
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