use the graph write ratio in simplest form
AB and BD for the first ratio, are pretty much given, just look at the x-coordinate values from A to B, and then from B to D EC is also just by looking at the y-coordinate, from E to C, how many units now, AE can be obtained by using pythagorean theorem AE = \(\sqrt{AC^2 + EC^2}\) now as far as the slopes of EB and ED just look at the points (x, y ) coordinates http://www.mathwarehouse.com/algebra/linear_equation/images/slope-of-a-line2.gif
so for 33 it is .....5/6
for 33, AC is 6 BD is 6 so the ratio of AC:BD is 6:6 that simplified is 1:1
can you explain it im sooo confused on how to do this
well AC is the length from point A to point C, which is 6 BD is the length from point B to point D, which is 6 #33 is asking for the ratio of AC/BD, which is 6/6 6/6 simplified is 1/1
oh i misread -_- ok
33 is simple because you can just count the distance from A to C and from B to D 34, you have to use the distance formula to find the distance from A to E
ok so refresh on how to do that
\[d=\sqrt{(x _{2}-x _{1})^2+(y _{2}-y _{1})^2}\]
\[AE = \sqrt{AC^{2} + EC^{2}}\]
but yes, what @Mertsj said haha
oh ok so how do i do that
well you know that AC is 6 find out what EC is by looking at the graph looks like EC = 8 so \[AE = \sqrt{6^{2}+8^{2}}\]
\[AE = \sqrt{36+64} = \sqrt{100} = 10\]
ohhh that makes sense
yep, not just do the same thing we did for 33
can you rephrase that for me
im confused as to what you mean
@nincompoop help me maybe...?
so what part are you confused?
what i am supposed to do after i have figured out what AE is
look for segment EC
ok i found it
it is 8..?
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