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This is kind of confusing> For f(m)=7^4-4m^2+8, find f '(x), f ''(x) and f '''(x). I'm not sure I understand. Isn't the derivative of a constant 0? I don't see how this can get down to f '''(x).
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find the limit if it exists.\[\lim (x,y) \frac{ xy-3 }{ x^{3}+y^{3} }\]
I've never seen a problem set up that way, so I don't understand lim (x,y)
anybody else know the answer for this???
wesdg, you'll have \[f'(m)=-8m\] \[f''(m)=-8\] \[f'''(m)=0\]
Ok, that's what I was thinking, but it seemed to simple to be right. thanks
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