Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2). y = x − 10

y =2/3 x + 10

y = −2/3x − 10

y = −2/3x + 10

Question

Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2). y = x − 10

 y =2/3 x + 10

 y = −2/3x − 10

 y = −2/3x + 10

anonymous · Answer

the first one by the equation is y=2/3x-10

anonymous · Answer

What does that  ".y = x-10" mean? Is It a typo?

anonymous · Answer

I think thats the first answer choice

anonymous · Answer

yeah its y=2/3x-10

anonymous · Answer

so@vinnv226 you think its the first one?

anonymous · Answer

hello?

texaschic101 · Answer

2x -3y = 3....we want y = mx + b form and m will be the slope
-3y = -2x + 3
y = -2/-3x + 3/-3
y = 2/3x - 1
the slope is 2/3
However you are looking for a perpendicular line....that means the slope is going to be the negative inverse of the slope....this means the slope you will need will be -3/2

now we have x = -8 and y = 2 and the slope(m) = -3/2

are you sure you wrote the problem correctly ? Because the slope for a perpendicular line is -3/2 and this does not match any of your answer choices.
Now if it a parallel line, then that will work with the slope of 2/3.