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Give the equation of a line that has a slope of 4 and passes through the point (3, –2). A. y = 4x – 14 B. y = –2x + 11 C. y = 3x – 14 D. y = –2x – 9
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if you plug in the slope and coordinates into \[y - y_{1}=m(x-x_{1})\] and solve for y you will have your y =mx +b equation :) i.e\[y +2 = 4(x-3)\] hope this was a nuff to get you started if not ask away :)
or u can use y=mx+c m=slope
yep thats the easy way ^ thanks for saying a alternate method XD
so with y=mx+b it is -2 = 4(3) + b ?
yep
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so -14 = b. what do I do next?
Is A correctttt??
yep..congrats..salu
thanks a lot:)
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