Question

Find coordinates of the point(s) of inflection for:

f(x)=x^4-4x^3+6x^2
f'(x)=4x^3-12x^2+12x
=4x(x^2-3x+3
Quad Form:
-(-3)+-sqrt(-3^2-4(1)(3)/2(1)
=3+-sqrt-3/2

Not sure what to do since the quad form. gives me an imaginary number.

Answer 1

Inflection is f '' not f '

Answer 2

\[f'(x)=4x^3-12x^2+12x\]
\[f''(x)=12x^2-24x+12=12(x^2-2x+1)=12(x-1)^2\]

Answer 3

f"=0
then sub that x value in original equation to get the y value