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Mathematics 21 Online
OpenStudy (anonymous):

Find the length of a leg.

OpenStudy (caozeyuan):

a leg of what, a man or a frog?

OpenStudy (anonymous):

|dw:1373292160552:dw|

OpenStudy (austinl):

Which leg?|dw:1373292234953:dw|

OpenStudy (anonymous):

i'm not sure, it only says "a leg"

OpenStudy (anonymous):

The legs are the same length, as it's a 45-45-90 right triangle

OpenStudy (ivettef365):

since it is an isosceles triangle x and y should have the same measurement

OpenStudy (caozeyuan):

well x^2+y^2=16^2, and x=y, so x=y=sqrt(2)*8 which is 11.3, approx.

OpenStudy (anonymous):

oh haha

OpenStudy (anonymous):

so what does that mean exactly?

OpenStudy (caozeyuan):

that means the length of both legs is 11.3

OpenStudy (anonymous):

that's not one of my options.

OpenStudy (caozeyuan):

what are, then?

OpenStudy (ivettef365):

you can do sin(45) = x / 16, in calculator it is 16 x sin(45) = x

OpenStudy (anonymous):

A. 2 radical 2 B. 8 radical 2 C. 16 D. 128

OpenStudy (caozeyuan):

well, B is my answer expressed slightly differently

OpenStudy (anonymous):

oh, ok! thank you :)

OpenStudy (anonymous):

?

OpenStudy (anonymous):

like the class i'm taking?

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