Find the inverse function of y=(4x-1)/(2x+3)
do you know the steps to find inverse function ? have you tried this one ?
I know the steps, but i'm confused as to whether to simply multiply 2x+3 across or not
yes, you should do that .....and tell me what u get ?
[(2x+4)*(Y)]/4=x
how did 2x+3 became 2x+4 ?
I brought the 1 over from the 4x-1 equation
added 1 to both sides.
the 1st step is to multiply 2x+3 (2x+3) y = 4x-1 got this ?
Yes.
good, now distribute the y (2x+3) y= ... ?
2xy+3y
then I move the 1 over, and divide by 4?
2xy+3y = 4x-1 the goal is to isolate 'x' , so bring all 'x' terms together for that you'll either need to bring 2xy on right or 4x on left do whatever you are comfortable with...
remember first bring all 'x' terms together
4x-2xy-1=3y
then, (4x-2xy-1)/3=y?
correct, also get rid of the 1 from left first so, after 4x-2xy-1 = 3y you would add 1 to both sides
What does that serve to accomplish? I thought the inverse function was to be expressed in terms of y?
in terms of 'y' , after you interchange 'x' and 'y'
ah, I had overlooked that. Thank you very much
the main point is to isolate other variable
lets continue ? 4x-2xy-1 = 3y then ?
4x-2xy=3y+1
Can we simplify left to be 2x(2-y)=3y+1?
correct!
now you can just divide both sides by 2 (2-y) and you would have isolated x :)
Then divide right side by 2(2-y), to isolate x variable?
Awesome, thank you very much for the professional walkthrough!
you got it :)
welcome ^_^
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