Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).
y = 2x + 6
y = −1/2x + 3
y = −1/2x + 6
y = 2x + 3
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OpenStudy (mikezack123):
@satellite73
OpenStudy (mikezack123):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
the slope of the line y = 2x+2 is m = 2 = 2/1
the perpendicular slope is found by flipping the fraction to go from
2/1
to
1/2
then flipping the sign to go from
1/2
to
-1/2
This means the perpendicular slope is -1/2
jimthompson5910 (jim_thompson5910):
with me so far?
OpenStudy (mikezack123):
fer sure
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jimthompson5910 (jim_thompson5910):
so we know that m = -1/2
jimthompson5910 (jim_thompson5910):
the line we want must pass through (6,3)
which means that when x = 6, y is y = 3
jimthompson5910 (jim_thompson5910):
y = mx + b
y = (-1/2)x + b ... plug in the slope we just found
3 = (-1/2)(6) + b .. plug in x = 6 and y = 3
now solve for b
jimthompson5910 (jim_thompson5910):
I'll let you take over from here
OpenStudy (mikezack123):
got it, its C
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