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Mathematics 15 Online
OpenStudy (anonymous):

. Find the perimeter of to the right with vertices A(-3,1), B (-1,3) and C(3,1)? Show your work.

OpenStudy (anonymous):

OpenStudy (anonymous):

of "rectangle ABC" to

OpenStudy (whpalmer4):

Why do you keep reposting this question?

OpenStudy (anonymous):

no this one is different actually

OpenStudy (whpalmer4):

no it's not!

OpenStudy (anonymous):

What information would you need to find the perimeter of to the right with vertices A(-3,1), B (-1,3) and C(3,1)? yes it is.

OpenStudy (whpalmer4):

that's the exact same question you've posted 6 times now. I'm looking at your list of posted questions.

OpenStudy (anonymous):

whatever

OpenStudy (whpalmer4):

go back to the one where we were working before you decided to take a 20 minute break or whatever. you weren't done.

OpenStudy (anonymous):

and i asked if it was 12 and you never answered back

OpenStudy (whpalmer4):

if you look, you'll see that I did.

OpenStudy (anonymous):

well you didnt on my screen

OpenStudy (whpalmer4):

go back and look. http://openstudy.com/study#/updates/51dc2a4ce4b0d9a104d9ce4c

OpenStudy (anonymous):

i did what you told me to do

OpenStudy (whpalmer4):

you didn't answer my question, and you didn't get the right answer. is 12 supposed to be the length of the final side of the triangle, or is it the perimeter? either way, it's wrong. do you want to find your mistake, or argue?

OpenStudy (anonymous):

well if you stop being impatient with me

OpenStudy (whpalmer4):

impatient? I've been working on this with you for over 2 hours, on and off. all I ask is that you do what I ask you to do.

OpenStudy (anonymous):

and i am

OpenStudy (whpalmer4):

no. I frequently ask you questions which you never answer. again: "is 12 supposed to be the length of the final side of the triangle, or is it the perimeter?"

OpenStudy (anonymous):

you said they were wrong!

OpenStudy (whpalmer4):

yes, they are wrong, but it still matters which part of the problem you were trying to answer! we need to find out WHY you got the wrong answer.

OpenStudy (whpalmer4):

so, again, just do as I ask, instead of arguing.

OpenStudy (anonymous):

and i dont know how i got the wrong answer okay

OpenStudy (whpalmer4):

which part of the problem were you trying to answer? was that the sum of the sides, or the length of the final side?

OpenStudy (whpalmer4):

okay, whatever. find the length of the side going from C to A on your diagram. all you have to do is count the marks on the grid between C and A.

OpenStudy (anonymous):

6

OpenStudy (whpalmer4):

right! now, add 6 + the two other sides we found. that's your perimeter.

OpenStudy (anonymous):

and thats how i got 12 6+4+2=12

OpenStudy (whpalmer4):

the other sides were not 4 and 2.

OpenStudy (whpalmer4):

they were \(2\sqrt{2} \approx 2.818\) and \(2\sqrt{5} \approx 4.472\)

OpenStudy (anonymous):

13.29

OpenStudy (whpalmer4):

yes, or \(6 + 2\sqrt{2} + 2\sqrt{5}\) if your system prefers a symbolic or exact answer.

OpenStudy (anonymous):

i just need to find the perimeter so whatever works

OpenStudy (whpalmer4):

whatever works is what your computer classroom software expects. I don't know what that is.

OpenStudy (whpalmer4):

13.29 is an approximation of \(6+2\sqrt{2}+2\sqrt{5}\)

OpenStudy (whpalmer4):

13.30 is a better approximation.

OpenStudy (anonymous):

ok now i need to find the area shall do in here still or shall i ask as another question?

OpenStudy (whpalmer4):

we can do it here. area of a triangle is given by\[A = \frac{1}{2}bh\] \(b\) is the length of the line across the bottom from A to C (or C to A, if you prefer). You already found that, do you remember the value?

OpenStudy (anonymous):

no

OpenStudy (whpalmer4):

well, then figure it out again....

OpenStudy (anonymous):

6?

OpenStudy (whpalmer4):

yes! :-)

OpenStudy (whpalmer4):

okay, now we need to find \(h\) which is the height of the triangle. You figured this out before, too. It's the distance from point B down to the line running between A and C.

OpenStudy (anonymous):

2

OpenStudy (whpalmer4):

okay, you know the formula, you know b, you know h, what's the area?

OpenStudy (anonymous):

its 1/2 x 6 x 2?

OpenStudy (whpalmer4):

yes

OpenStudy (anonymous):

then it is 6

OpenStudy (whpalmer4):

yes!

OpenStudy (whpalmer4):

you can eyeball the diagram and count squares to check the answer...

OpenStudy (whpalmer4):

there are three complete squares, plus two half squares under the line from A to B, plus 4 more half squares under the line from B to C 3 + 2(1/2) + 4(1/2) = 3 + 1 + 2 = 6

OpenStudy (anonymous):

ok im done for today

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