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Mathematics 8 Online
OpenStudy (anonymous):

Which of the following could not be a value of n? A. 7 B. 10 C. 13 D. 22

OpenStudy (anonymous):

OpenStudy (anonymous):

a^2+b^2=c^2

OpenStudy (calculusxy):

\[a^{2}+^b{2}=c^{2}\]

OpenStudy (chmvijay):

it cant be applied for this its only for recatnagel right

OpenStudy (calculusxy):

Yes your right.

OpenStudy (calculusxy):

@chmvijay

OpenStudy (anonymous):

is it a rt angle tri ..i dont thk so

OpenStudy (chmvijay):

its not right angel triangle

OpenStudy (anonymous):

now im even more confused.

OpenStudy (chmvijay):

LOL

OpenStudy (calculusxy):

@chicagoblkhaks Don't worry

OpenStudy (calculusxy):

Use the Law of Cosines. c^2 = a^2 + b^2 - 2*a*b*cos(C),

OpenStudy (anonymous):

i dont know how to do that, and i feel stupid saying it. but i dont.

OpenStudy (calculusxy):

c^2 = a^2 + b^2 - 2*a*b*cos(90) = a^2 + b^2 - 2*a*b*0 = a^2 + b^2

OpenStudy (calculusxy):

Use the source that I used. http://mathforum.org/library/drmath/view/54119.html

OpenStudy (calculusxy):

Did it help you? @chicagoblkhaks

OpenStudy (anonymous):

not a whole lot ...

OpenStudy (chmvijay):

why COS 90 its not right angel triangle @calculusxy

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