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OpenStudy (anonymous):
|dw:1373392174125:dw|
OpenStudy (johnweldon1993):
Well we would need to use an inverse trig function to solve this....we can use any function since we have all 3 sides...so which one do you want to use lol? sin^-1 , cos^-1 , or tan^-1?
OpenStudy (anonymous):
I have no ideaaaaa
OpenStudy (johnweldon1993):
lol well we'll do it using sin^-1
Okay well you know sin = opposite/hypotenuse right?
OpenStudy (anonymous):
Mhm
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OpenStudy (primeralph):
Do you have a calculator?
OpenStudy (anonymous):
Yes sir
OpenStudy (primeralph):
It's "Yes Your Highness"
What type is it?
Look for the sin-1 button.
OpenStudy (anonymous):
Idk Texas Instrument or something
OpenStudy (johnweldon1993):
So that means....from angle T we have
Opposite = 8
Hypotenuse = 17
so
\[\sin = \frac{ 8 }{ 17 }\]
Now...we use sin...when we know an angle...but...we need to FIND that angle...so we need to use the inverse sin function...so this should be written as
\[\sin^{-1} \frac{ 8 }{ 17 }\]
So on your calculator...press the 2nd button...then the sin button....this is your inverse sin function....then input 8/17 and press enter
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OpenStudy (primeralph):
Just use google then.
OpenStudy (anonymous):
I got 28
OpenStudy (anonymous):
Is that right?
OpenStudy (johnweldon1993):
That would be correct!
OpenStudy (anonymous):
Thank you :)
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