cos^2(pi/9) - sin^2(pi/9) Use identities to simplify. (Half angle and double angle)
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OpenStudy (itsonlycdeee):
Do you know your double angle formulas?
OpenStudy (anonymous):
yes but idk how yo use it with this problem
OpenStudy (itsonlycdeee):
Oh okay. Well cos(2A) = cos^2A - sin^2A or 1 - 2sin^2 A or 2cos^2A - 1, sin (2A) = 2sinAcosA and tan (2A) = 2tanA/1-tan^2A which formula do you think matches?
OpenStudy (anonymous):
cos(2A) = cos^2A - sin^2A
OpenStudy (itsonlycdeee):
Good and your A in this case is?
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OpenStudy (anonymous):
pi/6
OpenStudy (anonymous):
2 times pi/9 is pi/6
OpenStudy (anonymous):
sorry got that wrong
OpenStudy (itsonlycdeee):
Actually \[\frac{ 2\pi }{ 9 }\] can't be reduced. Since it was given to you in cos^2A -sin^2A . it becomes cos (2A) , which is just cos (2*pi/9).
OpenStudy (anonymous):
ok now do u plug in>
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OpenStudy (itsonlycdeee):
Well is your question looking for an answer or to just leave it as \[\cos \frac{ 2\pi }{ 9 }\] ?
OpenStudy (anonymous):
yeah it is asking for simplification. And it looks like it has been simplified. Thank you :)