Question

help

Answer 1

What have you got so far?

Answer 2

nothing I don't understand these

Answer 3

1,7,13 and 91

Answer 4

-7 and 13?

Answer 5

Good job! But I just realized since you're completing the square it's going to look like this: \[(x^2+ 6x + ____ ) = 91 \]

Answer 6

so what do we do?

Answer 7

If a^2 + bx +c is the standard formula and b = 6 to find c you use (b/2)^2. So plug that in and what do you get?

Answer 8

I thought the formula was a^2+2ab+b^2

Answer 9

It's the same thing because that equals (a+b)^2. I wrote it as a^2 + bx + c, so you can find/see c easily.

Answer 10

oh okay

Answer 11

So then did you find c, or according to the formula you used b^2?

Answer 12

oh no..

Answer 13

\[x^2+6x-91 = 0\]
\[x^2+6x+___ = 91\] & \[(\frac{ 6 }{ 2 })^{2} = 3^2 = 9\]

so x^2 + 6x + 9 = 91 + 9
(x + 3) ^ 2 = 100