Rafael has 1 black, 3 red, 7 green, 2 blue, and 2 yellow candies in his pocket.
What is the probability he will pull a red one out of his pocket? the answer is 3 right??
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OpenStudy (johnweldon1993):
Nooo not this one....15 total right? and there are 3 reds...so
P(red) = 3
---
15
OpenStudy (anonymous):
probabilities can never be greater than 1
probability of 1 means 100% surity of an event happening
OpenStudy (johnweldon1993):
and simplify that down a bit
OpenStudy (anonymous):
soo it is 1/3 ?!!?!?!?
OpenStudy (anonymous):
but i dont habe that option :(
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OpenStudy (johnweldon1993):
No....not 5
--
15
its 3
---
15
simplify THAT
OpenStudy (anonymous):
have*
OpenStudy (anonymous):
2/15??
OpenStudy (johnweldon1993):
\[\frac{ 3 }{ 15 } = \frac{ 1 }{ 5 }\]
3 goes into 15 5 times right?
OpenStudy (anonymous):
right
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OpenStudy (johnweldon1993):
Yeah...so 3/15 is simplified down to 1/5
OpenStudy (anonymous):
\[Probability = \frac{ number of favourable outcomes }{ Total number of outcomes }\]
favpurable outcomes = no. of balls of one kind
total no. of outcomes = total number of balls