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Limit as x approaches pi/2 from the negative for sec(3x)cos(7x)
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I would look at a graph, and find the answer. then I would use epsilon delta proof to prove it. I do not know of an elementary way to answer this. Normally I would say plug in pi/2 - .0000000000000001, but since this something with an oscillating amplitude, things tend to get funky around any "problem areas".
so you could get some very different numbers for pi/2 - 10^(-10) vs pi/2 - 10^(-11)
Have you learnt l'hopital's rule yet?
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