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substituting the p(x) where x=-5
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\[p(x) = 7x^{9} + 5x ^{8} - 4x ^{7} +10x ^{2} - 10\]
Plug in the -5 where the x's are and then combine like terms
\[7(-5)^{9}+5(-5)^{8}-4(-5)^{7}+10(-5)^{2}-10\]
yeah i do that one and the synthetic method but it didnt match .. so im putting it here 'cause i need some help
You can tell when the number after you square -5 and times it is going to be negative if the power is an odd and positive if the power is even does that make sense?
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