Question

Write the equation of a line in slope-intercept form that is perpendicular to the line y = three-fifths x minus 1 and passes through the point (-9, 4).

Answer 1

so you have y = 3/5x -1

Answer 2

yes

Answer 3

to be perpendicular the slope needs to be opposite reciprocal.
what is the slope on that equation

Answer 4

5/3 ?

Answer 5

the slope on that equation is actually 3/5

y = mx + b where m = slope

Answer 6

now what is opposite reciprocal of 3/5

Answer 7

5/3

Answer 8

the reciprocal is 5/3 but opposite reciprocal = -5/3

Answer 9

oh

Answer 10

now you need to find the equation of the line that goes through points (-9,4)
you use y = mx + b

you have m = -5/3
you have x = -9
you have y = 4

so the only thing you need to find is b

can you set it up to find b

Answer 11

I honestly have no idea

Answer 12

ok you have y = mx + b, to set up just substitute letters for the numbers it would look like this

4 = -5/3(-9) + b

Answer 13

now to solve for b as follows:

4 = (-5) (-3) + b
4 = 15 + b
4 - 15 = b
-11 = b

so b = -11

Answer 14

now the equation of the line perpendicular that passes through those points is

y = -5/3x -11

Answer 15

thanks ivettef365

Answer 16

yw :)