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y varies jointly with p and q when p=1 and q=2 y=30 so I have to find y when p = 10 and q= 3 im pretty sure the answer is 300 but I want to make sure
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Joint variation is z=kxy.
Or in your case, y=kpq where K is a constant number.
Soo 30=k(1)(2)
30=2k. What does K=? @johnrocks989
Once we have found K, which we know is 15 because 30/2 is 15 We plug in p and q So y=(15)(10)(3) So what does y=?
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this math is hurting my head lol thank you for helping me I think I have it now :) marrisa
You're welcome lol
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