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Mathematics 11 Online
OpenStudy (anonymous):

(x-5)(x+10)=0 help solve in quadratic equation

OpenStudy (mertsj):

If the product of factors is 0 then one of the factors must be 0.

OpenStudy (mertsj):

What factors are you multiplying?

OpenStudy (anonymous):

this is a quadratic equstion

OpenStudy (mertsj):

Yes it is.

OpenStudy (anonymous):

I am not sure how to work

OpenStudy (mertsj):

Can you solve this problem: x(2)(3)95)(-8) = 0 What is x?

OpenStudy (anonymous):

2 or 3?

OpenStudy (mertsj):

Let's say x = 2 as you suggest. So you believe that: 2(2)(3)(5)(-8)=0 ????

OpenStudy (anonymous):

no

OpenStudy (mertsj):

x(2)(3)(5)(-8)=0 What is x?

OpenStudy (anonymous):

1?

OpenStudy (mertsj):

So you believe that 1(2)(3)(5)(-8)=0 ????

OpenStudy (anonymous):

I give up I do not know

OpenStudy (mertsj):

Try this one: 5(x)=0 What is x ?

OpenStudy (anonymous):

i am here just thinking

OpenStudy (anonymous):

5

OpenStudy (mertsj):

So 5(5)=0 ????

OpenStudy (mertsj):

I will say it again: If you multiply factors and get 0 then one of the factors must be 0

OpenStudy (mertsj):

Solve this equation: 5x=0 by dividing both sides of the equation by 5

OpenStudy (anonymous):

I am lost

OpenStudy (mertsj):

5x=0 means that x has to be 0 because if the answer to a multiplication problem is 0 one of the numbers you multiply must be 0

OpenStudy (anonymous):

k so how do i solve my problem

OpenStudy (mertsj):

x-5=0 or x+10=0 Solve those equations.

OpenStudy (anonymous):

ok i think got what you are saying

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