Find the roots for the polynomial
y = x(x + 1)(x – 3)(x – 2√2)(x + 2√2).
A. 0, 1, –3
B. 0, –1, 3, –2√2, 2√2
C. –1, 3, –2√2, 2√2
D. 0, 1, –3, –2√2, 2√2

Question

Find the roots for the polynomial 
y = x(x + 1)(x – 3)(x – 2√2)(x + 2√2). 
	A.	0, 1, –3
	B.	0, –1, 3, –2√2, 2√2
	C.	–1, 3, –2√2, 2√2 
	D.	0, 1, –3, –2√2, 2√2

anonymous · Answer

just find what values for x would make y = 0

that means if any one of the parenthesis is 0, the y must equal 0 because anything times 0 is 0 :P

so for starters, since everything is multiply by that first x by itself, if x is 0, y is 0

so x=0 is one root

anonymous · Answer

now just do the same for the parenthesis

for the first parenthesis (x+1), if x = -1, then the parenthesis = 0, so that means y must = 0

so x = -1 is also a root

get it?

anonymous · Answer

i got it already! i googled it lol.

anonymous · Answer

thanks though!!!