Question

Find the roots for the polynomial
y = x(x + 1)(x – 3)(x – 2√2)(x + 2√2).
A. 0, 1, –3
B. 0, –1, 3, –2√2, 2√2
C. –1, 3, –2√2, 2√2
D. 0, 1, –3, –2√2, 2√2

Answer 1

just find what values for x would make y = 0

that means if any one of the parenthesis is 0, the y must equal 0 because anything times 0 is 0 :P

so for starters, since everything is multiply by that first x by itself, if x is 0, y is 0

so x=0 is one root

Answer 2

now just do the same for the parenthesis

for the first parenthesis (x+1), if x = -1, then the parenthesis = 0, so that means y must = 0

so x = -1 is also a root

get it?

Answer 3

i got it already! i googled it lol.

Answer 4

thanks though!!!