what is the contradiction of statement "m or n is even"?
neither (m or n is even), m and n are odd
oh.. what about the contrapositive statement for "m and n are both odd"?
contrapositive, as far as i can recall, relates to an if-then statement, a conditional statement
if p then q contraPs to: if notq then notp
yep.. the original statement is "if m*n is even, then m or n is even" ...
that makes more sense :)
if m*n is even, then m or n is even if -(m or n is even), then -(m*n is even) if (m and n are odd), then (m*n is odd)
(2n+1)(2k-1) (4nk +2k -2n) -1 2(2nk +k -n) -1 2m -1 is odd
thanks:) this helped a lot.. i m actually preparing for an exam and i bumped into this question... I didn't know what to do cause before, i bumped into a similar statement... the Q statement says "then m and n are both even or m and n are both odd" ... its contrapositive statement is "m or n is odd/even" ... i didn't know which one to use... XD
yeah, i tend to believe that reading shouldnt be required for math
-[ (m and n are both even) or (m and n are both odd)] -(m and n are both even) and -(m and n are both odd) (m or n is odd) and (m or n is even) then either m or n is odd, but not both at the same time. I believe thats an exclusive OR construct that is difficult to get across in words
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