Question

Please help! I'm solving a system of equations but I can't figure out what I'm doing wrong...
The system is:
3x - 6y = 12
-2x + 3y = 6

I distributed 2 to the second equation leaving me with -4x + 6y = 12
so then I got
3x - 6y = 12
-4x + 6y = 12
3x = 12
-4x = 12
-x = 0
x = 0
--------
3 (0) - 6y = 12
-6y = 12
y = -2

but my potential answers are 14, -14, 24 and -24

Answer 1

try to use substition instead :)

Answer 2

eq1 can be simplified into x=4+2y

Answer 3

what did you do to get that?

Answer 4

eq 1 divide by 3?
:)

Answer 5

I'll try that. I've never done substitution by dividing an equation before

Answer 6

this is good:
3x - 6y = 12
-4x + 6y = 12
add the equations to get
-1x + 0 = 24
or
-x = 24
x= -24

Answer 7

I think you confused adding /subtracting the equations
but you want to add because -6y + 6y = 0 (which is what you want)

Answer 8

haha, yea, didnt notice that small mistake xD

Answer 9

ahhh okay, thak you so much! I appriciate it!

Answer 10

so does y = -14?

Answer 11

yes

Answer 12

you can check you answers by putting x=-24 and y= -14 into each equation and seeing if they work. I just did, and both work

Answer 13

Thank you!

Answer 14

yw