Question

What is the distance between the point (-5, -4) and the line 2x + 3y + 5 = 0

Answer 1

A. 23
√13

B. 17
√13

C. 17
23

D. √23
17

Answer 2

option B

Answer 3

perpendicular distance of point (x1,y1) from line ax+by+c=0 is given by

\[|a*x1+b*y1+c| / \sqrt{a^{2}+b^{2}} \]

Here (x1,y1)=(-5,-4)
a=2
b=3
c=5

Answer 4

DIstance between a point (x,y) and a line ax+by+c is\[\frac{ ax+by+c }{\sqrt{a^2+b^2} }\]
modulus of it.

Answer 5

since distance=|(-5*2)+(-4*3)+5| /\[\sqrt{3^{2}+2^{2}}\]