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Mathematics 16 Online
OpenStudy (anonymous):

What are the possible number of positive, negative, and complex zeros of f(x) = -2x3 + 5x2 + 6x - 4 ? a.) Positive: 2 or 0; Negative: 1; Complex: 2 or 1 b.) Positive: 1; Negative: 2 or 0; Complex 2 or 0 c.) Positive: 2 or 0; Negative: 1; Complex: 2 or 0 d.) Positive: 1; Negative: 2 or 0; Complex: 0

OpenStudy (anonymous):

If you use Descartes' Rule of Signs and if you put in a negative value, you get 1 sign change, narrowing your answer to "a" or "c". If you put in a positive value, you get 2 sign changes, giving 2 or 0 for positive solutions. But the difference between "a" and "c" is that for a complex solution, they come in pairs, so you can't have "2" or "1", so your answer has to be "c".

OpenStudy (anonymous):

Good luck to you in all of your studies and thx for the recognition! @danny562

OpenStudy (jdoe0001):

http://www.youtube.com/watch?v=5YAmwfT3Esc

OpenStudy (anonymous):

thank you! i dont want you guys to think im just asking for the answers because the questions i post on here i really just dont get. and i like it when somebody explains it and also gives the correct answer i understand it now! thank you again. @tcarroll010

OpenStudy (anonymous):

You are very very welcome! I like that you want explanations! It shows that you are wanting to learn!

OpenStudy (anonymous):

ya haha i need the explinations because that does me no good for my tests and final if im just getting the answers.

OpenStudy (anonymous):

I really wish all the students here had your very good attitude!

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