What are the possible number of positive, negative, and complex zeros of f(x) = -2x3 + 5x2 + 6x - 4 ? a.) Positive: 2 or 0; Negative: 1; Complex: 2 or 1 b.) Positive: 1; Negative: 2 or 0; Complex 2 or 0 c.) Positive: 2 or 0; Negative: 1; Complex: 2 or 0 d.) Positive: 1; Negative: 2 or 0; Complex: 0
If you use Descartes' Rule of Signs and if you put in a negative value, you get 1 sign change, narrowing your answer to "a" or "c". If you put in a positive value, you get 2 sign changes, giving 2 or 0 for positive solutions. But the difference between "a" and "c" is that for a complex solution, they come in pairs, so you can't have "2" or "1", so your answer has to be "c".
Good luck to you in all of your studies and thx for the recognition! @danny562
thank you! i dont want you guys to think im just asking for the answers because the questions i post on here i really just dont get. and i like it when somebody explains it and also gives the correct answer i understand it now! thank you again. @tcarroll010
You are very very welcome! I like that you want explanations! It shows that you are wanting to learn!
ya haha i need the explinations because that does me no good for my tests and final if im just getting the answers.
I really wish all the students here had your very good attitude!
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