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Mathematics 20 Online
OpenStudy (anonymous):

what is the equivalent rational value of ;

OpenStudy (anonymous):

\[\sqrt[3]{64}\]

OpenStudy (anonymous):

do you know what the simplified form of \(\sqrt[3]{64}\) is?

OpenStudy (anonymous):

I don't know , I can try to figure it out but I don't know

OpenStudy (anonymous):

you know that \(\sqrt[3]{64}\) is read as "cube root of 64" right? that means you should think of a number that when you multiply it to itself 3 times, you get 64

OpenStudy (anonymous):

for example, 2 cubed is 2 x 2 x 2 = 8 or 3 cubed is 3 x 3 x 3 = 27

OpenStudy (anonymous):

so what number would make 64?

OpenStudy (anonymous):

oh , 8

OpenStudy (anonymous):

8 x 8 x 8 is 512 although, you're close since 8 x 8 is 64. but you need the number to be multiplied to itself 3 times

OpenStudy (anonymous):

ohhh sorry ! For 3 times it would be ; .. 21 x 21 x 21 is 64 ...

OpenStudy (anonymous):

that's 21 + 21 + 21 = 64 not times

OpenStudy (anonymous):

or is it 63 .. ugh

OpenStudy (anonymous):

I need help :/

OpenStudy (anonymous):

use trial and error on each number 1 x 1 x 1 2 x 2 x 2 3 x 3 x 3 4 x 4 x 4 5 x 5 x 5 etc.. one of those will give you 64

OpenStudy (anonymous):

ohh ... 4x4x4

OpenStudy (anonymous):

right

OpenStudy (anonymous):

so \[\sqrt[3]{64} = 4\] now, rewrite 4 as a fraction

OpenStudy (anonymous):

4 as a fraction ? how ? I forgot how to do that .

OpenStudy (anonymous):

think of a number that when you divide 4 by that number, you'll still get 4

OpenStudy (anonymous):

well that would be 1 .

OpenStudy (anonymous):

right. so 4 as a fraction is 4/1

OpenStudy (anonymous):

hat's your rational value now

OpenStudy (anonymous):

ohh right rght

OpenStudy (anonymous):

ok but the choices are a. 2 b. 8 c. 4 d. 21

OpenStudy (anonymous):

then choose 4. since 4/1 is also 4

OpenStudy (anonymous):

Good , so i was right ! Because I did some what of what you did then I did the 4x4x4 but just chose 4... >_< but atleast my answers right and now i remember .. THANKS!

OpenStudy (anonymous):

welcome

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