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Complete the square: 3x^2+7x-12 becomes x^2+7/4x=4 T or F?
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\( 3x^2+7x-12 = 0 \) First you must divide both sides by 3. you need \(x^2\) by itself.
first , coefficient of x^2 must be 1,so divide by 3
\( \dfrac{3}{3}x^2+\dfrac{7}{3} x -\dfrac{12}{3} = 0 \)
x^2+7/3x+4=0?
so it;s fasle?
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Good. \( x^2+\dfrac{7}{3} x - 4 = 0 \) \( x^2+\dfrac{7}{3} x = 4 \)
False. You are correct.
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