3x+2y=23 x+5z= -7 2y-z+16 How do you do this??? PLEASE HELP
Some substitution should do the trick: From equation 2: x = -7-5z
i know you use substitution but i still get stuck T.T
Plugging that instead of x into equation 1 gives us: 3(-7-5z) + 2y = 23, a bit of simplification will give us: -21-15z+2y=23 -15z+2y=23+21 -15z+2y=44
By the way is the third equation this: 2y-z=16 (= instead of +)
Hello?
oh srry let me try it out hold on
oh no it is +
hello???
@bahrom7893
It must have been a typo, that's impossible to solve otherwise.
so what do i do after i plugged in the x?
ohh no no yes yes it is = i was looking at the wrong + SORRY
so what do i do now? its narrowed down to -15z+2y=44 now what?
@bahrom7893
Plugging that instead of x into equation 1 gives us: 3(-7-5z) + 2y = 23, a bit of simplification will give us: -21-15z+2y=23 -15z+2y=23+21 -15z+2y=44 From the third equation find z: 2y-z=16 2y-16=z z=2y-16 Plugging this into the equation above: -15(2y-16)+2y=44
Solve for y, then find z, then find x
z = 2y-16 x = -7-5z
how do i solve for y though? i f i keep having two variables???
OHH wait wait nvm i get it i get it haha okay let me solve the whole thing and see if i get an answer :) THANK YOU SO MUCH :)
Go for it :)
I got the answer! It's 8 :) and it was one of the choices! Thank you! :) Do you mind helping me again later??? :)
@bahrom7893
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