Question

\sqrt[2]{-4 + 8 x}

Answer 1

\[\sqrt[2]{-4 + 8 x}\]?

Answer 2

we need to find the domain

Answer 3

set whatever is in the sqrt equal to \[\ge0\]

Answer 4

Because all square roots, on a graph have to be either equal or greater than 0, or else you get into the whole complex number conundrum so

Answer 5

\[-4+8x \ge0\] and now solve for x and that is your domain, understand?

Answer 6

i got x= 4/8 or 1/2 how do i put this as a interval notation