Question

If x^2 + 2xy+ y^2 = 25 what is the value of 4(x+y)^2?

Answer 1

@Loser66 @mathsuxx123 please help

Answer 2

@Zarkon please help too

Answer 3

Factor the left side.

Answer 4

Can you do that?

Answer 5

not rlly
i know it would be with x+y x+y but where would the 2 go?

Answer 6

(a+b)^2=a^2+2ab+b^2

Answer 7

(x+y)^2=x&2+2xy+y^2

Answer 8

oh okay and then what?

Answer 9

So the factors are (x+y)^2

Answer 10

so 25 times 4?

Answer 11

yep

Answer 12

yes

Answer 13

thanks!!!

Answer 14

yw

Answer 15

wait i have one more question!

Answer 16

ok

Answer 17

If x & y are both odd integers, which would also be an integer??

(x^2 - y^2)/(2)
(x^2 - y^2)/(3)

xy/2
xy/3
OR
xy/6
???

Answer 18

Did you try any of the answers?

Answer 19

i think its xy/3 but i dont really know how to approach this

Answer 20

You could say that an odd number is one more than an even number and could be represented by 2n+1, 2n+3 and so on.

Answer 21

so is xy/3 right?

Answer 22

no.
5 x 7 = 35 and 35/3 is not an integer

Answer 23

its x^2-y^2/3 ? :)

Answer 24

(2n+1)^2-(2n+3)^2=
4n^2+4n+1-(4n^2+12n+9)=
-8n-8

Answer 25

Looks to me like that is divisible by 2

Answer 26

OH yeah i meant 2

Answer 27

thank you! :)

Answer 28

yw