You roll 2 dice. What is the probability that the sum of the dice is less than 7 and at least 1 die shows a 3? (A 6 6 table of dice outcomes will help you to answer this question.)
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OpenStudy (anonymous):
this is a hard one
OpenStudy (anonymous):
no
OpenStudy (anonymous):
for me it is.
OpenStudy (anonymous):
tell me how to do it.
OpenStudy (anonymous):
dont just give me the answers...
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OpenStudy (anonymous):
its 1/12
OpenStudy (anonymous):
the probability you role a 3 is 1/6th
OpenStudy (anonymous):
now that you have 3 in order for the sum to be less then 7, the second dice must role less then 4
OpenStudy (anonymous):
the probability you role a dice with less then 4 is 1/2
OpenStudy (anonymous):
there mutually independent events, so the overall probability is 1/12
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OpenStudy (anonymous):
thats not an answer choice...
OpenStudy (anonymous):
what are the answer choices
OpenStudy (anonymous):
7/12
1/3
5/36
7/36
OpenStudy (anonymous):
order counts?
OpenStudy (anonymous):
does the 3 have to appear in the first role?
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OpenStudy (anonymous):
i believe so
OpenStudy (fifciol):
the probability is 5/36
OpenStudy (anonymous):
ye im to lazy to figure this out good luck
OpenStudy (anonymous):
proof pls
OpenStudy (anonymous):
5/36 because the first roll mus be a 3
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OpenStudy (fifciol):
you have only 5 possibilities:
first dice second dice
3 1
3 2
1 3
2 3
and
3 3
out of 6*6 possibilities of rolling two dices
OpenStudy (anonymous):
yeah i think hes right
OpenStudy (anonymous):
oh I see what you did there
OpenStudy (anonymous):
count the number of integers k on a die so that 3+k<7
OpenStudy (anonymous):
and multiply it by two for double pairs
and subtract 1 so you don't over count the 3,3
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OpenStudy (anonymous):
and divided by 36
OpenStudy (fifciol):
it could be done in that way but i prefer to simply write down the possibilities and count it when youre dealing with dice
OpenStudy (anonymous):
Fifciol you study mathematics
OpenStudy (anonymous):
i think i got it wrong
OpenStudy (anonymous):
thanks a lot..
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OpenStudy (anonymous):
no problem,
OpenStudy (anonymous):
study any analysis fifciol?
OpenStudy (fifciol):
mathematics is just a tool to solve problems but dont you want to make life easier? :)
OpenStudy (fifciol):
of course
OpenStudy (anonymous):
thats narrow minded lol, do you know about special functions?
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OpenStudy (anonymous):
like zeta functions/l functions etc
OpenStudy (fifciol):
yes i do
OpenStudy (anonymous):
do you know about euler products, those are nice
OpenStudy (anonymous):
like $$\prod_{p}(1+f(p)+f(p^2)+f(p^3)....)=\sum_{n=1}^\infty f(n)$$
OpenStudy (anonymous):
or is that to number theorish for u
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OpenStudy (fifciol):
i dealt with gamma function and i remember i solved those integrals for some simple numbers
OpenStudy (anonymous):
nvm, good luck with life or whatever
OpenStudy (fifciol):
do you believe that everything is written in numbers?
OpenStudy (anonymous):
that is kinda vague, what do you mean by that
OpenStudy (anonymous):
heres a nice telescoping sum, $$\frac{1}{\ln(q)}=\sum_{n=-\infty}^\infty\frac{2^n}{q^{2^n}+1}$$
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OpenStudy (anonymous):
i am a bit random
OpenStudy (fifciol):
you gotta be more pragmatic
OpenStudy (anonymous):
pragmatic?
OpenStudy (anonymous):
its 2:36 am in california, where are you?
OpenStudy (fifciol):
we're talking about problem with dice you're giving the wrong answer im trying to make you see it and then you show me a telescopic sum and tell that jack is not your name doont you think it kinda strange?
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