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How do you start simplifying the equation (cos(x)cot(x)/1-sin(x))-1?
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\[\frac{ \cos(x)\cot(x) }{ 1-\sin(x) }-1\] is this your question.
Yeah.
you can complete the answer.
Thanks!
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to me, I break the first term and the second term apart. second term is 1, let it there. now calculate the first term: \[\frac{cos *\frac{cos}{sin}}{1-sin}= \frac{\dfrac{cos^2}{sin}}{1-sin}\]time both numerator and denominator by (1+sin) \[\frac{\frac{cos^2}{sin}(1+sin)}{(1-sin)(1+sin)}=\frac{\frac{cos^2}{sin}(1+sin)}{1-sin^2}=\frac{\frac{cos^2}{sin}(1+sin)}{cos^2}\]cancel out cos^2 \[\frac{1+sin}{sin}=\frac{1}{sin}+1= csc +1\] now, add the second term from the beginning, that is -1 csc +1-1= csc
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