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Solve: negative 1 over 2 x + 2 = −x + 7 10 5 over 2 2 over 5 20
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Is this the original problem? \[\frac{-1 }{ 2x+2 } = -x+7\]
Multiply both sides by (2x+2) to get rid of the fractions \[\frac{ -1 }{ 2x+2 }(2x+2)=(-x+7)(2x+2)\]
\[Distribute (-2x^2-2x+7x+14)=-2x^2+5x+14\] Add one to both sides \[-1+(1)=(-2x^2+5x+14+(1))\] \[-2x^2+5x+15=0 \] Now factor and solve
its it ten
no, can you factor?
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I can help
ok it looks like its 20
My bad it was \[-2x^2+12x+14=-1 \] \[-2x^2+12x+15=0\]
it was 10
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what was the question? the one iw rote up there?
what
what was the original thing casue it look confusing
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