Question

this one

Answer 1

http://screencast.com/t/51jtlm8xbrfv

Answer 2

@theEric @souvik

Answer 3

I don't know that one off hand!

Answer 4

Sorry!

Answer 5

pressure of gas of X=h1*d*g
pressure of gas of Y=h2*d*g
here d is the density of mercury and g=gravitational acceleration..
you know the pressure of gasses in X and Y..the density of mercury is also given...u have to find h1 and h2

Answer 6

seperately right

Answer 7

can u do the working

Answer 8

i am doing for container X
16000=h1*13600*9.8
h1=0.12 m
=12 cm
can u do it for container Y?

Answer 9

i am getting 6 cm?

Answer 10

right !

Answer 11

but the answer is nt given

Answer 12

I did something mathy off of souvik's equations. I don't know the physis, though. Here's this:

Answer 13

X=h1*d*g.....(1)
Y=h2*d*g.....(2)

Divide equation (1) by equation (2) and you get
\[\frac{X}{Y}=2=\frac{h_1}{h_2}\Rightarrow h_1 = 2\ h_2\]

Answer 14

the answer (6 cm ) is given...2nd row 2nd column..

Answer 15

but for h1 we got 12cm

Answer 16

sorry i mean 2nd row 3rd column..

Answer 17

It makes sense that the \(h_1\) is greater than the \(h_2\) because \(X\gt Y\), but that's all the physicsy I can get on that one.

Answer 18

@souvik whats the correct answer

Answer 19

Didn't you say you worked these out, @zaphod ?

Answer 20

h1=12cm
h2=6 cm

Answer 21

yeah
i got C as my answer

Answer 22

but theres a confusion

Answer 23

Can you actually know an exact height in that problem? Even as a thought, you can scale that setup to be small enough to be on a desk, or as large as a building.

Answer 24

i dont get u

Answer 25

I'm not sure how it all works :P

Answer 26

whatever has been done is correct only if there is vaccum in tube P.

Answer 27

This has stuff on pressure difference and height of a fluid with a known density and gravitational acceleration.
http://hyperphysics.phy-astr.gsu.edu/hbase/pman.html

Answer 28

@Diwakar what is correct?

Answer 29

You could say \(h_1\) is dependent on \(P_X\) and \(P_P\),
while \(h_2\) is dependent on \(P_Y\) and \(P_P\).

Answer 30

@zaphod , at worst, you'll have to guess.

It's probably for a grade, right? So we can't answer it for you.. We can be your research tools, though.

Answer 31

It seems to be an "open internet" test, afterall..

Answer 32

after all*

Answer 33

no im preparing for exam

Answer 34

So this doesn't count? Will it tell you what the answer is?

Answer 35

nope unfortunately the marking scheme is not available

Answer 36

That's unfortunate. I guess if no one is certain, you could just guess what you \(know\) it isn't, so that way you can learn it and also factor it into the grade you get so you can know how you did with the exception of this question.

Answer 37

Good luck!

Answer 38

@Callisto

Answer 39

Px – P = d x g x h1
Py – P = d x g x h2

Work out h1 – h2 and check

Answer 40

So,we need not be given vaccum in the tube ,P. Just find the difference in the heights and then see which option fits that difference.Would not have worked if we were not given options.

Thanks @Vincent-Lyon.Fr