Question

Find critical values of y:
yln(y+2) = 0

Answer 1

for critical values you must take the first derivative and solve for
dy/dx = 0

Answer 2

I'm basically trying to get values of y. (for example on y-3 = 0 we know that y = +3. I just can't figure it out for this ln problem.

Answer 3

disregard the part that says critical value..

Answer 4

if your expression is \[y \ln(y+2)= 0\]than the answers are y = 0 and y = -1

recall that ln1 = 0