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Mathematics 16 Online
OpenStudy (anonymous):

Can anyone help with this? {Finding the length}

OpenStudy (anonymous):

OpenStudy (anonymous):

are you familiar with the distance formula?

OpenStudy (anonymous):

Not really.

OpenStudy (anonymous):

\[d = \sqrt{(x_2-x_1)^{2} + (y_2-y_1)^{2}}\] with two points (x1, y1) and (x2, y2)

OpenStudy (anonymous):

the points you are using in this problem are M(-2, -5) and N(-4, -4) so just plug them into the distance formula i gave you

OpenStudy (anonymous):

d= (-2-4) + (-5-4)= like that?

OpenStudy (anonymous):

look at the formula, you square each parenthesis, and the whole thing is square rooted

OpenStudy (anonymous):

also, you subtract the points, not add them... -5 - (-4) = -5 + 4

OpenStudy (anonymous):

-6, -1

OpenStudy (anonymous):

This is it?

OpenStudy (anonymous):

... do it for the other parenthesis too... then SQUARE both of them, add them, then take the square root of the whole thing. take a look at the equation i gave you

OpenStudy (anonymous):

How do i change it to square root form?

OpenStudy (anonymous):

you don't, it is already in square root form

OpenStudy (anonymous):

Yeah, i got -6 and -1 for both of them

OpenStudy (anonymous):

no, it is not -6 -2 - (-4) does not = -6

OpenStudy (anonymous):

Ohhh.. oops its 2.

OpenStudy (anonymous):

2, -1

OpenStudy (anonymous):

yes, now square both of those numbers

OpenStudy (anonymous):

square root of 2 is 1.4

OpenStudy (anonymous):

Im not getting the right answer.. :/

OpenStudy (anonymous):

not the square root, just SQUARE it, aka 2^2 and (-1)^2

OpenStudy (anonymous):

Ohh, 4 and -1

OpenStudy (anonymous):

so it should be square root of 3 right??

OpenStudy (anonymous):

(-1)^2 does not = -1

OpenStudy (anonymous):

thats what i got on my calculator..

OpenStudy (anonymous):

Thx.

OpenStudy (anonymous):

@ashleyvee you typed it in wrong then you will get this problem wrong

OpenStudy (anonymous):

No, i got it right.

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