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OpenStudy (anonymous):
OpenStudy (anonymous):
are you familiar with the distance formula?
OpenStudy (anonymous):
Not really.
OpenStudy (anonymous):
\[d = \sqrt{(x_2-x_1)^{2} + (y_2-y_1)^{2}}\]
with two points (x1, y1) and (x2, y2)
OpenStudy (anonymous):
the points you are using in this problem are M(-2, -5) and N(-4, -4)
so just plug them into the distance formula i gave you
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OpenStudy (anonymous):
d= (-2-4) + (-5-4)= like that?
OpenStudy (anonymous):
look at the formula, you square each parenthesis, and the whole thing is square rooted
OpenStudy (anonymous):
also, you subtract the points, not add them...
-5 - (-4) = -5 + 4
OpenStudy (anonymous):
-6, -1
OpenStudy (anonymous):
This is it?
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OpenStudy (anonymous):
... do it for the other parenthesis too... then SQUARE both of them, add them, then take the square root of the whole thing.
take a look at the equation i gave you
OpenStudy (anonymous):
How do i change it to square root form?
OpenStudy (anonymous):
you don't, it is already in square root form
OpenStudy (anonymous):
Yeah, i got -6 and -1 for both of them
OpenStudy (anonymous):
no, it is not -6
-2 - (-4) does not = -6
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OpenStudy (anonymous):
Ohhh.. oops its 2.
OpenStudy (anonymous):
2, -1
OpenStudy (anonymous):
yes, now square both of those numbers
OpenStudy (anonymous):
square root of 2 is 1.4
OpenStudy (anonymous):
Im not getting the right answer.. :/
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OpenStudy (anonymous):
not the square root, just SQUARE it, aka 2^2 and (-1)^2
OpenStudy (anonymous):
Ohh, 4 and -1
OpenStudy (anonymous):
so it should be square root of 3 right??
OpenStudy (anonymous):
(-1)^2 does not = -1
OpenStudy (anonymous):
thats what i got on my calculator..
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OpenStudy (anonymous):
Thx.
OpenStudy (anonymous):
@ashleyvee you typed it in wrong then
you will get this problem wrong