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Mathematics 18 Online
OpenStudy (anonymous):

The surface area of two similar figures are 25in^2 and 36in^2 If the volume of the smaller figure is 250in^3 what is the volume of the larger figure.

OpenStudy (mathstudent55):

If two similar figures have a scale factor of s, or a ratio of s/1 then the surface areas of the similar figures is in a ratio of s^2/1, and the volumes of the figures are in a s^3/1 ratio.

OpenStudy (jhannybean):

The key is to understanding the relationship between the measurement of volume and area.

OpenStudy (mathstudent55):

The area scale factor is \(s^2 = \dfrac{36}{25}\) Taking the square root of both sides, the linear scale factor is: \(s = \dfrac{6}{5} \) The volume sale factor is: \( s^3 = (\dfrac{6}{5})^3 = \dfrac{216}{125}\) \(250~in.^3 \times \dfrac{216}{125} = 432~in.^3 \)

OpenStudy (mathstudent55):

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