Which of the following is not an equivalent form of the compound inequality x + 15 less than or greater to 12 and x + 15 greater than or equal to 5 12 greater than or equal to x + 15 greater than or equal to 5 -3 greater than or equal to x greater than or equal to -10 A number line with a closed circle on -10, a closed circle on -3, and shading in between. A number line with a closed circle on -10, shading to the left, and a closed circle on -3, shading to the right.
@kelliegirl33
\(x + 15 \le 12\) and \(x + 15 \ge 5\) Subtract 15 from both sides in both inequalities: \(x \le -3\) and \(x \ge -10\)
x + 15 >= 5 x >= 5 - 15 x >= -10 x + 15 <>12 -- I don't understand the " less then or greater to" x <> 12 - 15 x <> -3 I don't know how to answer this with the " less then or greater to "
@sasogeek ...can you look at this please
I think he meant "less than or _equal_ to." Notice he used "to" instead of "than."
well that definitely makes a difference
x + 15 <= 12 x <= 12 - 15 x <= -3 so we have x <=-3 and x >= -10
@mathstudent55 ...can you help me with this ? If I go by this I know the last choice is incorrect. But I don't understand where the first two answer choices come in.
second choice is correct
ok...
The first choice is: A. \(12 \ge x + 15 \ge 5\) which is the same as \( 5 \le x + 15 \le 12 \)
That is exactly what the original statement means, so choice A is correct.
b is correct
c is correct
And Finally I am confused.
d is your answer
if its greater then,shading goes to the right....if it is less then, shading goes to your left
B. is correct because \(-3 \ge x \ge -10 \) means the same as my solution above, \(x \le - \) and \(x \ge -10 \), or \(-10 \le x \le -3\)
I believe the answer is D...what you think mathstudent ?
Choice C. is correct because it means \(-3 \le x \le -10\)
Choice D. means \(x \le -10 \) or \( x \ge -3 \) which is not the solution.
thanks for the help mathstudent.....the first choice confused me
and so did the less then or greater to
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