Question

write an equation of a line in slope intercept form that is perpendicular to y=-4x-2 and passes through the point (-16,-11)

Answer 1

what do you know of perpendicular slopes? anything?

Answer 2

um, i know some. but this particular type of problem gets me. im not sure to get the slope first or what. i think i have to input the pints, but when there are two sets of cordinants, i get confused. @dpaInc

Answer 3

well first, the line given is perpendicular to the line you need. what is the slope of the given line?

HINT: y=mx + b, "m" is the slope

Answer 4

-4

Answer 5

ok... good... the relation between perpendicular slopes is that they are NEGATIVE RECIPROCALS of each other...
in other words, \(\large m_1=\frac{1}{m_2} \)
so if m2 is -4, then the slope perpendicular would be \(\large \frac{1}{-4} \)
understand?

Answer 6

yes

Answer 7

good... since your question wants the equation in slope-intercept form, all we need now is the intercept because we know the slope is -1/4...

Answer 8

ok that makes sense

Answer 9

I see you...love the pony

Answer 10

lool love the eyes

Answer 11

so....
slope-intercept form: \(\large y=mx+b \)
we already know that the slope is -1/4 so: \(\large y=-\frac{1}{4}x+b \)
since we know the line passes through (-16, -11) plug these values into the above equation so we can solve for "b", the y-intercept...

Answer 12

you should be a teacher dpalnc :)

Answer 13

nah... i gave up on school... :(

Answer 14

ok. -11=11/4(-16)+b

Answer 15

what ?

Answer 16

i think u mean this: \(\large -11=-\frac{1}{4}(-16)+b \)

Answer 17

yah

Answer 18

now just solve for b

Answer 19

-51?

Answer 20

im only doing this so i can pass...
yep... solve for "b" and put it back into the equation: \(\large y=-\frac{1}{4}x+\color{red}b \)

Answer 21

-51 is not right... try again.

Answer 22

-15

Answer 23

there you go.. :)
nice work....

Answer 24

good job tyler :)

Answer 25

so your equation is y = -1/4x - 15