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subtract (6x^3-4x+5)-(2x^3-x^2+7x-10) in descending order
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will someone please help lol
I gave it a shot... can't guarantee this is right because I haven't taken a math course in a while but what I did was.... Subtract the x^3's first... so (6x^3-2x^3) = 4x^3 Then I subtracted the negative x^2 from the right side which gives us POSITIVE x^2 Then I subtracted 7x on the right from negative 4x on the left.... -11x Then subtract negative ten from five which is (5-(-10) --> (5+10) = 15 My end result was 4x^3 + x^2 - 11x + 15 Hope that helps!
okay thank you so much!
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