Question

find the inverse (if it exists) of f(x) 5x-4

Answer 1

f(x) = 5x - 4

y = 5x - 4 ... replace f(x) with y

x = 5y - 4 ... swap x and y

now solve for y

the solution you get will be the inverse

Answer 2

y= 4x/5?

Answer 3

not quite

Answer 4

\[\large x = 5y - 4\]

\[\large x+4 = 5y\]

\[\large 5y = x+4\]

\[\large y = \frac{x+4}{5}\]

Answer 5

so the inverse function is

\[\large f^{-1}(x) = \frac{x+4}{5}\]

Answer 6

oh i have to add the x to 4

Answer 7

okay!

Answer 8

yes

Answer 9

do you mind helping with one more?(:

Answer 10

sure

Answer 11

what's your question

Answer 12

for f(x)+ 4x+1 and g(x) = x^2 -2x-4 find (g-f)(x)

Answer 13

typo in f(x)+ 4x+1 ???

Answer 14

and then simplify it. this one seems hard

Answer 15

(g-f)(x) means g(x) - f(x)

Answer 16

yes f(x) =

Answer 17

so you are subtracting the two functions...ie the two expressions that make up the functions

Answer 18

so...

(g-f)(x) = g(x) - f(x)

(g-f)(x) = (x^2 -2x-4) - (4x+1)

(g-f)(x) = x^2 -2x-4 - 4x-1 ... don't forget to distribute fully

(g-f)(x) = ???

Answer 19

x^2+2x-3

Answer 20

is that right?

Answer 21

no

Answer 22

unfortunately it's not

Answer 23

dang it!

Answer 24

-2x - 4x = ??

Answer 25

its ok

Answer 26

-6x?

Answer 27

good

Answer 28

how about -4 - 1

Answer 29

-4 - 1 = ???

Answer 30

-5

Answer 31

(g-f)(x) = g(x) - f(x)

(g-f)(x) = (x^2 -2x-4) - (4x+1)

(g-f)(x) = x^2 -2x-4 - 4x-1

(g-f)(x) = x^2 - 6x - 5

Answer 32

and that's all there is to it

Answer 33

you are brilliant thank you

Answer 34

thanks for the compliment and I'm glad to be of help