Question

Factor the algebraic expression below in terms of a single trigonometric function.

sin 2x + sin x - 2

Answer 1

is it sin2x or sin^2x?

Answer 2

sin^2x

Answer 3

let x=sin^2x
so
x^2+x-2.........now factor it..

Answer 4

should i use the quadratic formula? @souvik

Answer 5

you may do this but u can factor it easily..

Answer 6

how?

Answer 7

do u know how to factor?

Answer 8

yeah

Answer 9

come on! try to o it...

Answer 10

i know how to use the quadratic formula but if there's an easier way i rather do it that way.

Answer 11

okay..did u find x?

Answer 12

how am i suppose to find x?

Answer 13

ok so doing the quadratic formula i got\[-1+- \sqrt{7}/2\]

Answer 14

\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
here a=1 ,b=1 and c=-2

Answer 15

yeah i did all of that and i got \[-1\pm \sqrt{7}/2\]

Answer 16

no...4ac=4*1*(-2)=(-8)
so b^2-4ac=1-(-8)=9

Answer 17

ok so when i do that i get -1 and -2

Answer 18

i mean positive 1

Answer 19

right..
So sinx=1...as\[-1\le \sin x \le1\]

Answer 20

so thats the answer ? sinx=1

Answer 21

sinx=1
or x=90 degree...!

Answer 22

alright, thanks

Answer 23

welcome..