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OpenStudy (anonymous):
checkkk my work?(:
Identify the oblique asymptote of f(x) = quantity x plus 4 over quantity 3 x squared plus 5 x minus 2
I got y = 3x - 7
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OpenStudy (rsadhvika):
check the question again, you didnt flip the expression ?
OpenStudy (rsadhvika):
x+4
------------
3x^2+5x-2
OpenStudy (rsadhvika):
its like that ?
OpenStudy (anonymous):
yes
OpenStudy (rsadhvika):
then no oblique asymptote, cuz numerator degree is less. it will have a horizontal asymptote at y=0. thats all
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OpenStudy (anonymous):
y = 3x - 7
y = 3x + 17
y = 0
No Oblique Asymptote
these are the answer choices..
OpenStudy (rsadhvika):
tick No Oblique Asymptote
OpenStudy (anonymous):
okay. help me with one more?!?!?! pleeeeaseesssss?
OpenStudy (rsadhvika):
sure :)
OpenStudy (anonymous):
Identify the oblique asymptote of f(x) = quantity 4 x squared minus x plus 2 over quantity x plus 1
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OpenStudy (anonymous):
and these are my answer choices!
y = 4x - 5
y = 4x + 3
y = 0
No Oblique Asymptote
OpenStudy (rsadhvika):
numerator degree > denominator degree
so it will have a oblique asymptote
when u divide, you would get
y = 4x-5
OpenStudy (anonymous):
Thank you so sos so sosososososoo much!
OpenStudy (rsadhvika):
np :)
OpenStudy (lakota1999):
right
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