Question

checkmy worrrrk?(:










What is the simplified form of 2 over x squared minus x minus 1 over x ?
x minus 1 over the quantity x times x plus 1
1 minus x over the quantity x times x plus 1
3 minus x over the quantity x times x minus 1
x plus 2 over the quantity x times x minus 1
I got A...

Answer 1

Your sentences are difficult to read sometimes :D lol
Is it suppose to look like this?\[\large \frac{2}{x^2}-x-\frac{1}{x}\]

Answer 2

te x is supposed to be with the x^2 under 2..sorry Idk how to paste it here without it turning this way/;

Answer 3

\[\large \frac{2}{x^2-x}-\frac{1}{x}\]
Ah ok :O i see. sec, working through it.

Answer 4

okay!

Answer 5

Hmm, I don't think it's A.
Want to see some of the steps to figure out where u went wrong? :U

Answer 6

yes!

Answer 7

We need a common denominator, which in this case will be the product of the denominators. \(\large x(x^2-x)\)

So it looks like our first fraction needs to be multiplied by \(\large \cfrac{x}{x}\)
while our second fraction should be multiplied by \(\large \cfrac{x^2-x}{x^2-x}\)

Which will give us,\[\large \frac{2x}{x(x^2-x)}-\frac{1(x^2-x)}{x(x^2-x)} \qquad=\qquad \frac{2x-(x^2-x)}{x(x^2-x)}\]

Answer 8

Lemme know if any of those steps are too confusing :o

Answer 9

That's how we would combine the fractions, then from there we can simplify by doing some fancy stuff.

Answer 10

I got that

Answer 11

Distributing the negative on top gives us,\[\large \frac{2x-x^2+x}{x(x^2-x)} \qquad=\qquad \frac{3x-x^2}{x(x^2-x)}\]Did you remember to distribute that negative sign? :)

Answer 12

ohhh no. I didn't do that

Answer 13

Bahh easy spot to make a mistake D: poor gal.

Answer 14

so is it C?

Answer 15

Yay good job \c:/

Answer 16

thank you so much! big help!(: